What is the difference between string and stringbuilder in c#

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In C#, both string and StringBuilder are used to work with textual data, but they have different characteristics and are optimized for different scenarios. Here's an overview of the differences between the two:

Immutability:

String: In C#, a string is immutable, which means that once a string object is created, its value cannot be changed. Any operation that modifies a string actually creates a new string object.

StringBuilder: On the other hand, StringBuilder is mutable, allowing you to modify the contents of the string without creating a new object each time. This can be more efficient when you need to perform multiple modifications on a string.

Performance:

String: Since strings are immutable, performing operations such as concatenation or insertion can be inefficient because they require creating new string objects. In scenarios where you need to perform a large number of string manipulations, the performance can degrade due to memory allocations and object creation.

StringBuilder: StringBuilder is designed to address the performance issues associated with frequent string modifications. It provides methods such as Append, Insert, Replace, etc., which modify the underlying string buffer efficiently. By using StringBuilder, you can avoid unnecessary memory allocations and improve performance.

Usage:

String: string is commonly used when you have a fixed string value or when you need to perform operations that don't involve frequent modifications, such as string comparisons, searching, or substring extraction. It is also the preferred choice when working with string literals or constants.

StringBuilder: StringBuilder is useful when you need to perform frequent modifications on a string, such as building a dynamic string by appending or inserting values in a loop. It is particularly efficient when dealing with large strings or when you concatenate a significant number of smaller strings together.

In summary, if you have a scenario where you need to perform frequent modifications on a string, it is more efficient to use StringBuilder to avoid unnecessary object creation and improve performance. However, for scenarios involving fixed or unchanging strings, or when you need to perform operations that don't modify the string, using the string type is sufficient.

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what is deep copy and shallow copy In C#

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In C#, as in other programming languages, you may encounter the terms "deep copy" and "shallow copy" when working with objects and data structures. These two concepts refer to the different ways in which data can be copied from one variable to another. Let's take a closer look at what deep copy and shallow copy mean in C#, and when to use each one.

Shallow Copy

A shallow copy in C# creates a new object but does not create new copies of the objects within the original object. Instead, the new object contains references to the objects in the original object. Therefore, changes made to the original object will also affect the new object, and vice versa.

Here's an example to illustrate shallow copy in C#:

int[] originalArray = {1, 2, 3}; int[] newArray = (int[])originalArray.Clone(); // modify the original array originalArray[0] = 5; // both the original and new arrays have changed Console.WriteLine(string.Join(",", originalArray)); // 5,2,3 Console.WriteLine(string.Join(",", newArray)); // 1,2,3

In the example above, originalArray is an array of integers. We make a shallow copy of it using the Clone() method and casting the result to the array type, and store it in newArray. Then, we modify the first element of originalArray. As a result, both originalArray and newArray are updated because they both refer to the same underlying objects.

Deep Copy

A deep copy in C# creates a new object and recursively creates new copies of the objects within the original object. In other words, it creates a completely independent copy of the original object, so changes made to the original object will not affect the new object, and vice versa.

Here's an example to illustrate deep copy in C#:

using System; using System.Collections.Generic; using System.Linq; class Person { public string Name; public List<string> Hobbies; } class Program { static void Main(string[] args) { var originalPerson = new Person() { Name = "John", Hobbies = new List<string>() { "reading", "running" } }; var newPerson = new Person() { Name = originalPerson.Name, Hobbies = new List<string>(originalPerson.Hobbies) }; // modify the original person originalPerson.Name = "Jane"; originalPerson.Hobbies.Add("swimming"); // only the original person has changed, the new person remains unchanged Console.WriteLine(originalPerson.Name); // Jane Console.WriteLine(string.Join(",", originalPerson.Hobbies)); // reading,running,swimming Console.WriteLine(newPerson.Name); // John Console.WriteLine(string.Join(",", newPerson.Hobbies)); // reading,running } }

In the example above, we define a Person class with a name and a list of hobbies. We create a new instance of Person called original Person and initialize its name and hobbies. Then, we create a new instance of Person called newPerson and initialize its name to originalPerson.Name and its hobbies to a new list created from originalPerson.Hobbies. This creates a deep copy of original Person because the new list created from originalPerson.Hobbies is a new object.

Then, we modify the name and hobbies of original Person. As a result, only original Person is updated, and new Person remains unchanged.

When to Use Shallow Copy and Deep Copy

Which one you use depends

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8 Things You Don't Want to Hear About Difference between Html.Partial() and Html.RenderPartial() in ASP.NET MVC

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Html.Partial()

Html.Partial returns html string.

Html.Partial injects the html string of the partial view into the main view.

Performance is slow.

Html.Partial() need not to be inside the braces.

Html.RenderPartial()

Html.RenderPartial returns void.

Html.RenderPartial writes html in the response stream.

Perform is faster compared with HtmlPartial().

Html.RenderPartial must be inside braces @{ }.

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What Is loading program in c language and How Does It Work?

In this program, we will learn how to make c language loading program with graphical mode.

To understand this program, you must have this knowledge:

• Basic c
• function
• structure
• loop
• ascii

source code: loading program in c language

#include<stdio.h> #include<conio.h> #include<graphics.h> #include<dos.h> #include<stdlib.h> void LOAD(); struct det input(); void display(struct det); struct det { char string[50]; int roll_no; }; void main() { textcolor( LIGHTMAGENTA); struct det d2; clrscr(); printf("\t\t\tWelcome ancientcode\n"); printf("\t\t\tAncientcode1.blogspot.com\n"); getch(); textcolor(RED); d2=input(); clrscr(); LOAD(); textcolor(LIGHTBLUE); clrscr(); display(d2); getch(); } det input() { struct det d1; printf("\nEnter Your Name:"); gets(d1.string); printf("\nEnter Your Roll No:"); scanf("%d",d1.roll_no); return(d1); } void display(struct det d) { srand(time(0)); printf("\n\n\t\t\tWelcome User\n\n\n\n"); printf("\n User Id : %d\n",rand()); printf(" Name : %s\n",d.string); printf(" Roll No : %d",d.roll_no); } void LOAD() { _setcursortype(0); int j; for(j=30;j<=50;j++) { textbackground(WHITE); gotoxy(j,13); cprintf(" "); } gotoxy(34,14); printf(" LOADING...."); textbackground(LIGHTGREEN); for(j=30;j<=50;j++) { gotoxy(j,13); cprintf(" "); gotoxy(38,13); delay(100); } textbackground(0); gotoxy(34,14); printf(" COMPLETED "); gotoxy(27,16); printf("PRESS ANY KEY TO CONTINUE"); }

Remember: if you run this code you have a need to turbo c/c++.

Click: Turbo

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How To Teach palindrome program in c Like A Pro

In this post, we will talk about the palindrome program in c And we will know. What is a palindrome? And how to make the Palindrome program.

To understand this program, you must have this knowledge:

• Basic c
• if-else
• loop
• function
• string
• pointer
• enum

what is Palindrome?

In the most simple terms, a palindrome is a word, phrase, or number which reads the same backwards as it does when being read forwards. it does not matter if there are punctuation marks within the palindrome

these do not count and if they are present, the sequence or word will still fall under the category of the palindrome.

the word palindrome originally comes from the greek language and is made up of two words, the first being palin which translates to mean again and the second being dromos which translates to mean direction or way.

the palindrome, when read backwards will have the same pattern, layout, appearance, sound, and meaning. For the use of the palindrome in the English language, we can thank a man named Ben jonson who introduced the idea way back in the 17th century.

Palindrome example:

    
	stats, madam, wow, 
    level, refer
    191 225522
    222 9955599

source code: palindrome program in c

#include <stdio.h> #include <string.h> char *Reverse(char *); enum String oracle(char*, char* ); enum String { not_palindrome, palindrome }; int main() { enum String s1; char Rstring[20], Ustring[20], Nstring[20]; printf("\t\t\tString palindrome Program"); printf("\nEnter your String: "); gets(Ustring); strcpy(Nstring, Ustring); strcpy(Rstring, Reverse(Ustring)); s1 = oracle(Nstring, Rstring); if (s1 == 1) printf("palindrome:%s", Rstring); else printf("Not palindrome:%s ", Rstring); } enum String oracle(char Nstring[], char Rstring[]) { int orange; orange=strcmp(Nstring,Rstring); if (orange== 0) return (palindrome); else return (not_palindrome); } char *Reverse(char *code1) { int i, l; char Ancien_code; for (l = 1; *(code1 + l); l++); for (i = 0; i < l / 2; i++) { Ancien_code = *(code1 + i); *(code1 + i) = *(code1 + l - 1 - i); *(code1 + l - 1 - i) = Ancien_code; } return (code1); }

Output Screen

    Enter your String: computer
	Not palindrome:retupmoc 
     
    Enter your String: level
    palindrome:level
    

Program Logic

First, we will take input in an array named Ustring.

Then we will copy the string in the Nstring array with the help of strcpy function.

Will create another strcpy function. Nstring and reverse function will pass in it. We will pass Ustring in reverse function.

From here the cursor will go to the definition of the reverse function. In the argument bracket of the reverse function, we will create a pointer named code1.

Inside the reverse we will make i and l. And we will create an ancientcode variable of type char.

Then we will put a loop. The length of string will be obtained with the help of l and code1.

Put another loop And in that i will run till length/2.

Then inside the loop we will do swapping with the help of pointer. After that function will return value of code1.

now cursor will move on previous position where reverse function call was made.

The reverse function that will return the value. The same will be copied to Rstring.

We will then call the Oracle function. And will pass Nstring and Rstring in it. The cursor will go to the oracle function. Then the code of the Oracle function will be executed.

Inside the function, we will create an orange variable. we will call the strcmp function then will pass Nstring, Rstring. strcmp will return an integer value that will be assigned to a variable named Orange.

Then we will apply the if-else condition. And will check. if orange equal to 0 So the return is a palindrome variable. Otherwise, return no_palindrome variable. Then the Oracle function will return value. that value will be assigned to s1.

Here we will once again apply the if-else condition. if s1 equal to 1. So the string is a palindrome. Otherwise, there is no palindrome.

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Here's A Quick Way To Solve A Problem with #define in c

In this post, we will teach you what is #define in c and how it is work. #define in c is a very simple topic so we telling this topic.

To understand this program, you must have this knowledge:

• Basic c

what is #define in c?

a macro is an identifier defined in a #define preprocessor directive.

the #define directive defines an identifier and a character sequence a set of characters that will be substituted for the identifier each time it is encountered in the source file.

the identifier is referred to as a macro name and the replacement process as macro replacement.

as with symbolic constants, the macro identifier is replaced in the program with the replacement text before the program is compiled.

macros may be defined with or without arguments.

a macro without arguments is processed like a symbolic constant.

In a macro with arguments, the arguments are substituted in the replacement text, then the macro is expanded.

source code: program simple Interest with #define in c

#include <stdio.h> #define Intrest(p, r, t) (p * r * t) / 100 void main() { int pri, rate, time; float Si; printf("Enter pri,rate,time: "); scanf("%d%d%d", &pri, &rate, &time); printf("\nIntrest: %1.4f", Si = Intrest(pri, rate, time)); printf("\nYour simple Intrest is: %1.4f", pri + Si); return 0; }

Output Screen

    
Enter pri, rate, time : 5000 10 1

Intrest : 500.0000 
Your simple Intrest is : 5500.0000

Program Logic

We will include #define as a header file.

We just have to write #define. Then the name of the macro and the character-sequences.

We just have to take input from the user. whose macro we created. Have to pass the value in it. The macro will calculate and give the result.

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In c language output screen text color

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In this program, we are telling this. How to change the text color of the output screen.

   
   
  #include
#include
int main()
{
    int i;
    for(i=0;i<15;i++){
      SetConsoleTextAttribute(GetStdHandle(STD_OUTPUT_HANDLE),i);
    printf("hello world\n",i);
    }
 
}
                 

Output Screen

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Number searching program through enum in c

In this post, we will create a search program with the help of enum. This is a very simple and easy method for creating number search program and We will learn what is enumerator. What is its use in c language? how the enumerator is implemented in the program.

To understand this program, you must have this knowledge:

• Basic c
• if-else
• loop
• function

what is enumerator?

1. It gives an opportunity to invent own data type and define what values the variable of this data type can take.

            enum month 
            {
                sun, mon, tue, wed, thu, fri, sat
            };
            
            
            main()
            {
                enum week we1,we2;
            }  
        

2. each value on the list of permissible values corresponds to an integer, starting with 0. In the example sun is stored as 0, mon is stored as 1 ........, sat is stored as 6.
3. you can manually assign value in enum

            enum month 
            {
             sun=1, tue=4, fri=5
            };
        

4. we can initialize enumerators with different integer values.
5. you can write any program in c language without the help of enumerations but enumerations helps in writing clear codes and simplify programming

Now, let us go to the example enum program.

Source code: enum in c program

#include<stdio.h> enum search Ncheck(int,int,int ); enum search { not_found,found }; int main() { int n,R,maxR; enum search Fnumber; printf("\t\tNumber Search program"); printf("\n\nEnter range number: "); scanf("%d%d",&R,&maxR); printf("\n\n\nSearch your number: "); scanf("%d",&n); Fnumber=Ncheck(n,R,maxR); if(Fnumber==1) { printf("\nNumber is found: %d",n); } else { printf("Number is not found: %d",n); } } enum search Ncheck(int n,int R, int maxR) { int i; for(i=R;i<=maxR;i++) { if(n==i) { return(found); } } return(not_found); }

Output Screen

            Enter range number: 12
            99
            
            Search your number: 55
            Number is found: 55
            
            Enter range number: 1
            10

            Search your number: 15
            Number is not found: 15

          

Program Logic

First of all we are taking two inputs from the user. In the variable R and maxR

So that we know the range of numbers.

After that, those numbers will be input. Which to find in that range.

Then we will call the Ncheck function. And pass n, R, maxR.

Inside the Ncheck function we will place a loop. Then we will assign R inside i and i<=maxR.

Inside the loop, we will check through the if condition. If the condition of n==i is true, then return. Found variable

If the condition is false. So the loop is complete. And then return. not_found variable

Ncheck will return the function value from here. Which will be assigned to a variable named Fnumber.

Then we will apply the if-else condition. And will check. What condition is true if Fnumber==1. So we have got the number. The othervice condition is false. Not received

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coprime number program

In this program, we will discuss the program of co-prime numbers. What are co-prime numbers? How to make co-prime number program.

To understand this program, you must have this knowledge:

• basic c
• if-else
• loop

what is coprime number?

A set of numbers which do not any other common factor other than 1 are called co-prime numbers.

This means those numbers whose HCF is 1.

For example, 7 and 11 no other common factor other than 1 so they are coprime numbers.

if more information

Now, let us go to the program.

Source code: coprime number program

#include<stdio.h> void main() { int n,a,i,b,big; printf("Enter two number: "); scanf("%d%d",&a,&b); if(a==b) { printf("these number are not co prime number: %d %d",a,b); } else { big=a>b?a:b; for(i=2;i<big;i++) { if(a%i==0&&b%i==0) { break; } } if(i==big) { printf("%d and %d are coprime number",a,b); } else { printf("these number are not coprime number:%d %d",a,b); } } }

Output Screen

 
            Enter two number: 8
            6
            8,6 are not coprimes
            Enter two number:7
            11
            7,11 are coprimes
        

Program logic

First of all, we will take two inputs from the user. Then we will assign it to the variables namedaand b.

After that, we will apply the if-else condition. And will put the expression in the if condition or if the condition of a==b is true. So both these numbers are not coprime. If false. Then you will move on the else block.

In the body of else, we will use the conditional operator. Will check both of these. Which is the bigger number? Which is bigger. It will be assigned to a variable named big.

Then we will apply a loop. In which i will start the value from 2. And from i<big.

Inside the loop, we will apply the if condition. If that condition is true. So the break keyword goes. And move out of the cursor loop. And move to the next line. If the condition is not true. So the loop is complete. And then the next line has come.

Once again we will apply the if-else condition. And will check i==big. If there is. So a and b are coprime numbers.

If the value of i is not equal to big. So both numbers are not coprime.

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The Ultimate Secret Of function overloading in c++

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How to write function overloading program in c++

Explain function overloading in c++ with an example so that we can understand the function overloading program.

It is a function overloading program. In this, we have told this. how to get lcm, If inputs are received from the user two or three. In this program, you will understand How to program function overloading.

To understand this program, you must have this knowledge:

• basic c++
• loop
• conditional operator
• if
• switch case
• function

What is function overloading?

In c++ is a feature of function overloading. function overloading is an example of compile-time polymorphism.

where two or more functions can have the same name but parameters are different.

the polymorphism implements three categories:

compile-time polymorphism

function overloading

operator overloading

runtime polymorphism

virtual function

How can I resolve function overloading?

these simple ways,

1. first, c++ tries to find an exact match. this is the case where the actual argument exactly matches the parameter type of one of the overloaded functions.


2. if no exact match is found, c++ tries to find a match through the promotion


• char, unsigned char, and short is promoted to an int.


• float is promoted to double


3. if no promotion is found, c++ tries to find a match through standard conversion.

Now, let us go to the program.

First of all, you can imagine the output screen then build your logic.

        Enter two number:6
        16
        LCM is 48

        Enter three number:12
        6
        7
        LCM is 84
        

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Example: function overloading in c++

#include <iostream> #include <conio.h> using namespace std; int lowestM(int, int); int lowestM(int, int, int); int main() { while (1) { int ch; cout << "\t\tLCM Program" << endl << endl << endl; cout << "1. LCM of two number" << endl; cout << "2. LCM of three number" << endl << endl << endl; cout << "Enter your choice : "; cin >> ch; switch (ch) { case 1: int num1, num2; cout << "Enter two number:"; cin >> num1 >> num2; cout << "LCM is " << lowestM(num1, num2); break; case 2: int num3, a, b; cout << "Enter three number:"; cin >> b >> a >> num3; cout << "LCM is " << lowestM(a, b, num3); break; case 3: exit(0); break; default: cout << "Try again: Invalid Input"; } getch(); system("Cls"); } } int lowestM(int num1, int num2) { int L, Y; L = num1 > num2 ? num1 : num2; Y = L; for (L; L <= num1 * num2; L = L + Y) { if (L % num1 == 0 && L % num2 == 0) { break; } } return (L); } int lowestM(int num1, int num2, int num3) { int L, Y; L = num1 > num2 ? num1 > num3 ? num1 : num3 : num2 > num3 ? num2 : num3; Y = L; for (L; L <= num1 * num2 * num3; L = L + Y) { if (L % num1 == 0 && L % num2 == 0 && L % num3 == 0) { break; } } return (L); }


Output Screen

Program Logic

This is a program of lcm. We have made a program to check lcm of numbers two and three.

First, we put a while loop inside the main function. Which will run the infinite. Then inside it took input from the user and stored it in a variable named ch.

Within this while loop, we created a switch-case and passed the ch variable to the parentheses of the switch.

Now the number will be input by the user. The same case will work.

Inside the first case, we took input in num1 and num2. Then passed to the lowestM function.

Similarly, we did the same in the second case. But taking three inputs.

case three, we created the exit function. To end the program. And for the default simple message.

After that, we created two functions with the same name but there is a difference in argument. Which is an example of function overloading.

In both functions, we used the conditional operator. Which shows which number is bigger.

We will store that big number in L variable.

Here we will take a new variable named Y and assign the value of L to it.

Then we will apply a loop. In which L is less than or equal of num1 * num2 And add to L the value of Y. Then assign L

Put an if condition in the body of the loop. In which num1 and num2 will divide to L.

If the condition is true. Then the break keyword in the body of it will run. And the value of L will be the return.

Our result is the return value. And we will get lcm of two number.

Similarly, we will also get lcm of number three.

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Program find next prime number

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In this post, we will tell about the next prime number program. So please read this post carefully so that you can understand the program of next prime number.

First of all, you can imagine the output screen

Enter any number: 17

19 Next prime number:

Enter any number: 16

17 Next prime number:

Enter any number: 36

37 Next prime number:

you must have this knowledge

basic cpp, loop, if-else

Source Code next prime number 

#include<iostream> using namespace std; int main() { int n,i; cout<<"Enter any number: "; cin>>n; n=n+1; for(i=2;i<n;i++) { if(n%i==0) n=n+1; } cout<<n<<" Next prime number: "; }

Output Screen







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Define two overloaded versions of function calculating volume of sphere and cuboid

Source code function overloading sphere and cuboid 

#include <iostream> using namespace std; float volume(float); int volume(int,int,int); int main() { int sp; cout << "Enter sphere value: "; cin >> sp; cout << endl; cout << "The sphere volume is: " << volume(sp); int l, w, h; cout << endl; cout << "Enter cuboid lenth breath and hight: "; cin >> l >> w >> h; cout << endl; cout << "volume of cuboid is: " << volume(l, w, h); } float volume(float num1) { return ((4 * 3.14* num1 * num1 * num1)/3); } int volume(int l, int b, int h) { return (l * b * h); }


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factorial program in cpp using function

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In this example, we will explain to you write a factorial program in c++. To understand this topic it is necessary to have knowledge of basic CPP, function, and loop. Please read this article carefully so that you can understand the factorial program in c++.

First of all, you can imagine the output screen then build your logic.

 Enter N number : 5

factorial of 5 is 120

You must have this knowledge

basic CPP, function, loop

Program logic

Create a variable named n of int type. Then take input into it.

After taking the input call the function named pro. And pass n variable to it.

Create a fact name variable inside the pro function and assign 1 to it.

Then put a loop. And i = 1 in the condition of the loop. And run up to i<= n. And when the condition of the loop is true. So multiply the fact with i variable inside the loop. result Assign to the fact.

This way the loop will continue. Until 1 is equal to n.

After the loop is over, the return statement will run. then The cursor will move on from where the function call was made. After this, the result will be printed.

Source code factorial program in cpp using function

#include <iostream> using namespace std; int pro(int); int main() { int n; cout << "Enter N number : "; cin >> n; cout << "factorial of " << n << " is " << pro(n); return 0; } int pro(int n) { int pro = 1; for (int i = 1; i <= n; i++) { pro = pro * i; } return (pro); }

Output Screen

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HCF program default arguments in cpp

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write a c++ program to find HCF of two numbers and three numbers with help of the default argument.

You must have this knowledge

basic CPP, pointer, conditional operator, loop, if-else

HCF program default arguments in cpp

// default argument example //this program run two times for HCF of two numbers and three number. #include <iostream> using namespace std; int number1, number2;//global declartion varible int *c = &number2;//global pointer int HCF(int &, int &, int = *c); //*c contain address number2 varible int main() { cout << "\t\t\t HCF PROGRAM" << endl << endl << endl; cout << "Enter two number : "; cin >> number1 >> number2; cout << "HCF of two number is: " << HCF(number1, number2); cout << endl; int number3; cout << "Enter three number : "; cin >> number1 >> number2 >> number3; cout << "HCF of Three number is:" << HCF(number1, number2, number3); } int HCF(int &num1, int &num2, int num3) { int small; small = num1 < num2 ? num1 < num3 ? num1 : num3 : num2 < num3 ? num2 : num3; while (small) { if (num1 % small == 0 && num2 % small == 0 && num3 % small == 0) break; small--; } return (small); }

Output Screen

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C++ Program to Check Whether a Number is Prime or Not

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how to write a CPP program to check the prime number. and how can we solve this prime number program? In this post, we explain how to check the prime number program. Knowledge of CPP is necessary to understand this program.

what is a prime number?

The prime number is that. Which is divisible by 1 and is divisible by itself and apart from that, is not divisible by anyone else. We are only talking about positive integer here. 

Click on this prime number for more details.

now,

solving approach is that.

First of all, you can imagine the output screen then build your logic.

Enter a number: 17

17 is a prime number

Enter a number: 6

6 is not a prime number

You must have this knowledge

Basic CPP, loop, if-else

Program Logic

You have to declare three variables. int type i, fresh=0, prime

Now take the input in the step named prime.

Apply the loop condition, initialize i=2 in the loop condition Then you should continue the loop. Until i is equal to prime.

We will put an if condition inside the body of the loop. And this time the value of fresh is 1. if condition is true. So it means that not a prime number. If not true. So the if condition will not work. And will reach the endpoint of the loop. Then the value of i will be incremented. And the loop will run again.

the loop will run repeatedly. Until the value of i is equal to the prime variable. And then when the value of i is equal to the prime variable. then the condition of the loop will be false.

now, cursor move on the next statement.

Now the if condition outside the loop will be checked.

After this, if the prime variable is equal to i-1. Still not that prime number. And if not equal i-1. So that number is a prime number.

Source code prime number programming in c

#include <iostream> using namespace std; int main() { int prime,fresh=0,i; cout<<"Enter a number: "; cin>>prime; for(i=2;i<prime;i++) { if(prime%i==0) { cout<<prime<<" is not a prime number"; fresh=1; break; } } if(prime==i-1) cout<<prime<<" is not a prime number"; else if(fresh==0) { cout<<prime<<" is a prime number"; } return 0; }

This is another method. To check the prime number programming in c.

source code prime number programming in c

#include <iostream> using namespace std; int main() { int prime,i; cout<<"Enter a number: "; cin>>prime; for(i=2;i<prime;i++) { if(prime%i==0) { break; } } if(i==prime) cout<<prime<<" is a prime number"; else cout<<prime<<" is not a prime number"; return 0; }

Output Screen

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c program pattern 4

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In this program we will write c program pattern 4, we will understand how a pattern is made To understand this pattern, you must have basic C knowledge and loop information so that you can understand well.

First of all, you can imagine the output screen then build your logic.

^^^^^

^^^^

^^^

^^

^

You must have this knowledge

basic c,  nested loop

Program Logic

1. first of all, declare i and j
2. applying nested loop
3. i and j variables decide which position is print.
4. check this condition j<=6-i

c program pattern 

#include<stdio.h> int main() { int i,j; for(i=1;i<=5;i++) { for(j=1;j<=6-i;j++) { printf("^"); } printf("\n"); } return 0; }

This is the second approach program

c program logical ^ pattern 

#include<stdio.h> int main() { int i,j; for(i=1;i<=5;i++) { for(j=i;j<=5;j++) { printf("^"); } printf("\n"); } return 0; }

Output Screen





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