The Ultimate Secret Of function overloading in c++

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How to write function overloading program in c++

Explain function overloading in c++ with an example so that we can understand the function overloading program.

It is a function overloading program. In this, we have told this. how to get lcm, If inputs are received from the user two or three. In this program, you will understand How to program function overloading.

To understand this program, you must have this knowledge:

• basic c++
• loop
• conditional operator
• if
• switch case
• function

What is function overloading?

In c++ is a feature of function overloading. function overloading is an example of compile-time polymorphism.

where two or more functions can have the same name but parameters are different.

the polymorphism implements three categories:

compile-time polymorphism

function overloading

operator overloading

runtime polymorphism

virtual function

How can I resolve function overloading?

these simple ways,

1. first, c++ tries to find an exact match. this is the case where the actual argument exactly matches the parameter type of one of the overloaded functions.


2. if no exact match is found, c++ tries to find a match through the promotion


• char, unsigned char, and short is promoted to an int.


• float is promoted to double


3. if no promotion is found, c++ tries to find a match through standard conversion.

Now, let us go to the program.

First of all, you can imagine the output screen then build your logic.

        Enter two number:6
        16
        LCM is 48

        Enter three number:12
        6
        7
        LCM is 84
        

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Example: function overloading in c++

#include <iostream> #include <conio.h> using namespace std; int lowestM(int, int); int lowestM(int, int, int); int main() { while (1) { int ch; cout << "\t\tLCM Program" << endl << endl << endl; cout << "1. LCM of two number" << endl; cout << "2. LCM of three number" << endl << endl << endl; cout << "Enter your choice : "; cin >> ch; switch (ch) { case 1: int num1, num2; cout << "Enter two number:"; cin >> num1 >> num2; cout << "LCM is " << lowestM(num1, num2); break; case 2: int num3, a, b; cout << "Enter three number:"; cin >> b >> a >> num3; cout << "LCM is " << lowestM(a, b, num3); break; case 3: exit(0); break; default: cout << "Try again: Invalid Input"; } getch(); system("Cls"); } } int lowestM(int num1, int num2) { int L, Y; L = num1 > num2 ? num1 : num2; Y = L; for (L; L <= num1 * num2; L = L + Y) { if (L % num1 == 0 && L % num2 == 0) { break; } } return (L); } int lowestM(int num1, int num2, int num3) { int L, Y; L = num1 > num2 ? num1 > num3 ? num1 : num3 : num2 > num3 ? num2 : num3; Y = L; for (L; L <= num1 * num2 * num3; L = L + Y) { if (L % num1 == 0 && L % num2 == 0 && L % num3 == 0) { break; } } return (L); }


Output Screen

Program Logic

This is a program of lcm. We have made a program to check lcm of numbers two and three.

First, we put a while loop inside the main function. Which will run the infinite. Then inside it took input from the user and stored it in a variable named ch.

Within this while loop, we created a switch-case and passed the ch variable to the parentheses of the switch.

Now the number will be input by the user. The same case will work.

Inside the first case, we took input in num1 and num2. Then passed to the lowestM function.

Similarly, we did the same in the second case. But taking three inputs.

case three, we created the exit function. To end the program. And for the default simple message.

After that, we created two functions with the same name but there is a difference in argument. Which is an example of function overloading.

In both functions, we used the conditional operator. Which shows which number is bigger.

We will store that big number in L variable.

Here we will take a new variable named Y and assign the value of L to it.

Then we will apply a loop. In which L is less than or equal of num1 * num2 And add to L the value of Y. Then assign L

Put an if condition in the body of the loop. In which num1 and num2 will divide to L.

If the condition is true. Then the break keyword in the body of it will run. And the value of L will be the return.

Our result is the return value. And we will get lcm of two number.

Similarly, we will also get lcm of number three.

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